A 20m deep well with diametre 7m is dug and the earth from digging is evently spread out to form a platform 22m by 14m.Find the height of the platform?
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volume of deep = volume of platform
1/3×22/7×20×3.5×3.5 = 22×14×h
h = 2.5/3
1/3×22/7×20×3.5×3.5 = 22×14×h
h = 2.5/3
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⇒ Given:- Height (h) of well :- 20m
Diameter (d) :- 7 m
Radius (r) :- 7/2 m
Volume of earth platform :- 22 m by 14m
⇒ To find :- Height of the platform:- ?
⇒ Solution:-
Volume of cylinder of radius 7/2 m and height 20 m
Volume of cylinder :- π(r^2)(h)
= 22/7×(7/2^2)×20 m^3
= 770 m^3
Let the height raised by 22 m × 14 m platform be equal to h metres
Therefore,
Volume of the earth in platform = Volume of the earth taken out of the well
22 × 14 × h = 770
h = 770/22 × 14 m
h = 5/2 m
h = 2.5 m
Hence , the height of the platform is 2.5 m.
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