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21. Ir two dice are thrown once. Find the probability of getting the sum of the digits on
the faces of the dice is 8.
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Answers
Answered by
3
Answer:
p(e)= no of favourable cases /total no of cases
p(e)=5/36
Step-by-step explanation:
face of two dice
1,1 ; 1,2 ; 1,3 ; 1,4 ; 1,5 ; 1,6
2,1 ; 2,2 ; 2,3 ; 2,4 ; 2,5 ; 2,6
3,1 ; 3,2 ; 3,3 ; 3,4 ; 3,5 ; 3,6
4,1 ; 4,2 ; 4,3 ; 4,4 ; 4,5 ; 4,6
5,1 ; 5,2 ; 5,3 ; 5,4 ; 5,5; 5,6
6,1 ; 6,2 ; 6,3 ; 6,4 ; 6,5 ; 6,6
now, sum of face of dice is 8 in 5 cases
Answered by
0
Answer:
Answer is 5/36
Step-by-step explanation:
(2,6) (6,2) (3,5) (5,3) (4,4).
THESE ARE THE FAVOURABLE OUTCOMES FOR THE GIVEN QUESTION.
SO,
P(SUM OF DIGITS ON TOP FACE IS 8) = NO.OF FAVOURABLE OUTCOMES / TOTAL NO.OF OUTCOMES
TOTAL NO.OF OUTCOMES WHEN WE THROW 2 DICE ARE 36 I.e 2n^2
P(SUM OF DIGITS ON TOP FACE IS 8) = 5/36
HOPE IT HELPS YOU.
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