Question

A 21 m deep well with diameter 6 m is dug and the earth from digging is evenly spread to form a platform 27 m X 11 m. Find the height of the platform. (Use $\pi =\frac{22}{7}$)

Answer 1

Answer:

h=2m.

Step-by-step explanation:

Given,depth of well=21m

Radius of well=6/2=3

Volume of earth dugout from the well=πr^2h

22/7×3×3×21

=594m^3

Let the height of the platform=h m.

Volume of platform=volume of earth dugout

27×11×h=594

h=594/27×11=594/297

so height of the platform,h=2m.