Question

A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s. What is the 3250 kg car's initial velocity?

Answer 1

Answer:

hy

Explanation:

Momentum is conserved hence sum of initial momentum equals the sum of final momentum

$m1*v1+m2*v2\\=m1+m2/ve$

where  is the mass of 2150 Kg car,  is the mass of 3250 Kg car,  is the velocity of the 2150 Kg car,  is the velocity of the 3250 Kg car,  is the common velocity

Making  v2 as the subject then

$m1* m2/ve-m1v1/m2$

Substituting 2150 Kg for , 3250 Kg for , 10 m/s for , 5.22 m/s for  then we obtain

$2.0578\\=2.1m/s$