A 21m deep well with diameter 6m is dug and the earth from digging is evenly spread to form a platform (27m(11m).Find the height of the platform.
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15
the well will be in the cylindrical shape. its radius r =7/2m
and height h =20 m.
the volume of the earth dug out =π*r*²*H / b*l
area of the platform= 22*14 m square
let the height of the platform be H m.
volume of the platform = volume of the earth dug out
22*14*H=22*35
H=35/14=5/2=2.5 m.
and height h =20 m.
the volume of the earth dug out =π*r*²*H / b*l
area of the platform= 22*14 m square
let the height of the platform be H m.
volume of the platform = volume of the earth dug out
22*14*H=22*35
H=35/14=5/2=2.5 m.
Answered by
5
Answer:
r = 6/2 = 3m
h = 21m
volume in m*3 = ¶ r*2h
22/7 x 3 x 3 x 21 = 22 x 3 x 3 x 3 = 22 x 27 = 594m*3
length = 27m , breadth = 11 m
h = Volume/ l x b = 594/27x11 = 2 m
so, height = 2 m
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