Math, asked by manandviji, 11 months ago

A 21m wide athletic track consist of two straight sections 150m long joining semicircular ends whose external diameter is 84 m find the area

Answers

Answered by amitnrw
20

Answer:

14616 m²

Step-by-step explanation:

External Diameter = 84 m

=> Internal Diameter - 84 - 21 - 21 = 42 m

Area of two straight sections 150m long & 21 m wide

= 2 * 150 * 21

= 6300 m²

Area of 2 Semicircular Sections

= 2 * ( Area of External semi circle - Area of Internal Semicircle)

= 2 * ( π * 42²  - π 21²)

= 2 * π 21²  ( 4 - 1)

= 2 * (22/7) * 21² * 3

= 44 * 21 *  9

= 8316 m²

Total Area of Track = 6300  + 8316  = 14616 m²

Answered by sanskritisharma10c
2

Answer:

answer is 14616 m².

Step-by-step explanation:

it is in the attachment.

Attachments:
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