A 21m wide athletic track consist of two straight sections 150m long joining semicircular ends whose external diameter is 84 m find the area
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Answered by
20
Answer:
14616 m²
Step-by-step explanation:
External Diameter = 84 m
=> Internal Diameter - 84 - 21 - 21 = 42 m
Area of two straight sections 150m long & 21 m wide
= 2 * 150 * 21
= 6300 m²
Area of 2 Semicircular Sections
= 2 * ( Area of External semi circle - Area of Internal Semicircle)
= 2 * ( π * 42² - π 21²)
= 2 * π 21² ( 4 - 1)
= 2 * (22/7) * 21² * 3
= 44 * 21 * 9
= 8316 m²
Total Area of Track = 6300 + 8316 = 14616 m²
Answered by
2
Answer:
answer is 14616 m².
Step-by-step explanation:
it is in the attachment.
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