Question

a 22-k resistor and a 0.02-f capacitor are connected in series with 5 v source. how long it will take to charge a capacitor to .34 v

Answer 1

Answer:

oh h it Dr it Dr it to if Dr it Dr it Dr u du u dry it f

Answer 2

Answer:

The time that will take to charge the capacitor is 1.182 seconds.

Explanation:

Given:

Vc=0.34V

Resistance(R)=22

Capacitor(C)=0.02

To find: Time(t)=?

Solution:
We know that,

The voltage across the capacitor is given by,

$Vc = V (1 - e^{(-t/RC)} )$

0.34 =5$(1 - e^{(-t/RC)} )$

0.34/5=$(1 - e^{(-t/RC)} )$

$(1 - e^{(-t/RC)} )$=0.068

Taking natural log on both sides,

$\frac{-t}{RC} = -2.688$

$t=2.688*22*0.02$

∴t=1.182 seconds

Therefore, the time that will take to charge the capacitor is 1.182 seconds.