Question

A 22-ounce bowl of crackers contains 18 percent cheese crackers. Aida computed 18 percent of 22. Her work is shown below.


Write 45 percent as 9 ´ 5 percent, and write 5 percent as 1/20 . Then, find 1/20 of 75: 75 times StartFraction 1 Over 20 EndFraction = StartFraction 75 Over 20 EndFraction = 3.75. Multiply 3.75 by 9 to get 33.75. So, 45 percent of 75 is 33.75.

Write 45 percent as 9 ´ 5 percent, and write 5 percent as One-half. Then, find One-half of 75: 75 times one-half = StartFraction 75 Over 2 EndFraction = 33.75. Multiply 33.75 by 9 to get 303.75. So, 45 percent of 75 is 303.75.

Write 45 percent as StartFraction 1 Over 45 EndFraction. Then, find StartFraction 1 Over 45 EndFraction of 75: 75 times StartFraction 1 Over 45 EndFraction = StartFraction 75 Over 45 EndFraction = 1.67. So, 45 percent of 75 is 1.67.

Write 45 percent as StartFraction 1 Over 4.5 EndFraction. Then, find StartFraction 1 Over 4.5 EndFraction of 75: 75 times StartFraction 1 Over 4.5 EndFraction = StartFraction 75 Over 4.5 EndFraction = 16.7. So, 45 percent of 75 is 16.7.
Pls answer quicker!

Answer 1

Answer:

776566+6+6+665+55+55×6666÷6666777+6777

Answer 2

Answer:

777655+6+6+655+789+01