Question

A 220 long train passes a signal post in 22 second. Find the speed of the train?



$l = d \div t$
​

Answer 1

• Speed of the train in meter = 10 m/s.

OR,

• Speed of the train in kilometer = 36 km/hr.

Given :–

• Distance (d) = 220 m long.
• Time taken (t) = 22 sseconds.

To Find :–

• Speed of the train.

Solution :–

We know that,

in

$\bullet \: Speed = \dfrac{Distance}{Time}$

$\longmapsto\cancel \dfrac{220}{22} \: m/s$

$\longmapsto \dfrac{10}{1} \: m/s$

$\longmapsto10 \: m/s$

The speed is in the form of m/s (meter per seconds),

In kilometer per hour (km/hr),

We have to multiply $\dfrac{18}{5}$ by speed (m/s).

Here,

• Speed = 10 m/s.

So,

$\longmapsto\cancel{10}\times \dfrac{18}{ \cancel5} \: km/hr$

$\longmapsto2 \times \dfrac{18}{1} \: km/hr$

$\longmapsto 2 \times 18 \: km/hr$

$\longmapsto 36 \: km/hr$

Hence,

The speed of the train in meter = 10 m/s.

OR,

The speed of the train in kilometer = 36 km/hr.

Answer 2

Answer:

$\sf \large \bullet \: given \: \\ \\ \sf \implies{ \boxed{ \red{distance(length \: of \: train) = 220m}}} \\ \\ \sf \implies{ \boxed{ \blue{time = 22 \: s}}} \\ \\ \sf \large \:to \: find \\ \\ \implies \sf{ \boxed{speed = \frac{distance}{time}}} \\ \\ \sf \implies \: speed \: = \frac{220}{22} m {s}^{ - 1} \\ \\ \sf \implies \large{ \boxed{ \pink{speed = 10 \: m {s}^{ - 1}}}}$

Therefore , speed of the train is 10 m/s