A 220 v and 800 w electric kettle and three 220 v and 100 w bulbs are coonected in paralle on connecting this combination with 220 v electric supply the total current will be
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resistance of kettle = V^2 / P = 220 x 220 / 800 = 484 / 8 ohm
Resistance of each bulb = V^2 / P = 220 x 220 / 100 = 484 ohm
Now 484/8 , 484, 484, 484 are connected in parallel to a supply of 200 V
Effective resistance = 484/11 ohm
So current in the circuit = 200/ (484/11) = 2200/484 = 4.55 A
Resistance of each bulb = V^2 / P = 220 x 220 / 100 = 484 ohm
Now 484/8 , 484, 484, 484 are connected in parallel to a supply of 200 V
Effective resistance = 484/11 ohm
So current in the circuit = 200/ (484/11) = 2200/484 = 4.55 A
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