Question

A 220v,50hz ac supply is connected across a resistor of 50kohm.The current at time t seconds assumingg that it is 0 at t=0 is

Answer 1

Answer:

I= V/Z . Given V= 220 V , f= 50 Hz, where the impedance Z=R+jXL. On magnitude wise Z = sqrt(R^2+XL^2)

XL= 2*pi*f*L;

the previous current in the circuit is 220/ 100 = 2.2 A. The current need to be half. Then, Ireq=1.1 A

XL^2= (V/I)^2-R^2;

Hence,

L= sqrt(((V/I)^2-R^2))/2*pi*f

where I= 1.1 A

Hence, L= 0.5513 H

Answer 2

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—) L= 0.5513 H