Question

a 220v Dc shunt motor at no load takes a current of 2.5A the resistance of the armature and shunt field are 0.8 ohm and 200 ohm rest.the constant losses of motor in watt is?ans=548.4​

Answer 1

Answer:

Voltage (V) = 220 V

No load current (INL) = 3 A

Full load current (IFL) = 25 A

Full load speed (NFL) = 1500 rpm

Armature resistance (Ra) = 0.5 Ω

Shunt resistance (Rsh) = 220 Ω

Shunt current

Armature current (Ia) = IL - Ish

When motor is operating at no load

IanL = INL - Ish = 3 – 1 = 2 A

Eb1 = V - IanL Ra

= 220 – (2) (0.5) = 219 V

When motor is operating at full load

IaFL = IFL - Ish = 25 – 1 = 24 A

Eb2 = V – IaFL Ra

= 220 – (24) (0.5) = 208 V

We know that, in a DC shunt motor

Eb α N

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