Question

a 23m 75cm high water tank cast a shadow 20m long. Find at the same time : 1= the length of the shadow cast by a tree 9m 50 cm high

Answer 1

Answer:

9.2 m

Step-by-step explanation:

Height of tank = 23 m 75 cm = $23+\frac{75}{100}=23.75 m$

Length of shadow of tank = 29 m

Height of tree = 9 m 50 cm = $9+\frac{50}{100}=9.5 m$

Let the length of shadow of tree be x

So, ATQ

$\frac{23.75}{29}=\frac{9.5}{x}$

$x=\frac{9.5 \times 23}{23.75}$

$x=9.2$

Hence the length of shadow of tree is 9.2 m

Answer 2

Answer: 8m

Step-by-step explanation:

23 m and 75 cm = 23.75 m

9m and 5 cm = 9.5 m

23.75 m = 20 m (shadow)

9.5 m = 9.5*20 / 23.75

9.5 m = 190 / 23.75

9.5 m = 8 m (shadow)

Hope this helps you guys!