A 240m long train crosses aplatform having length of twice of the train's length in 4 sec. What is the speed of train
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- Question⇒ A 240m long train crosses aplatform having length of twice of the train's length in 4 sec. What is the speed of train.
Explanation:
- length of the train is 240m
- Platform length is 2 times the length of the train 2*240=480
- The train engine should start at the beginning of the platform and the last coach should end at the end of the platform
- Additionally the train has to move 240 m to cross the platform because the end coach should leave the platform
- 480+240=720
- Distance =720m
- Time=4 sec
- Velocity =distance /time
- =720/4
- =180m/sec
- 18o*18/5=64.8kmph
- the speed of the train is 648kmph
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