Physics, asked by nishatrivedi, 11 months ago

A 25 cm long closed organ pipe resonates with a tuning fork at 40 degree Celsius . determine the frequency of the fork . the speed of sound in air at 0 degree Celsius is 330 m/s.​

Answers

Answered by Utkarsh1507F
7

Answer:

Speed of sound in air and length of the pipe are represented by v and L respectively.

Frequency of different modes of vibration in a closed organ pipe, ν

n

=

4L

(2n−1)v

For length of the pipe to be a, f=

4a

(2n−1)v

⟹(2n−1)v=4af ...................(1)

For length of the pipe to be b, f=

4b

(2[n+1]−1)v

f=

4b

(2n+1)v

⟹(2n+1)v=4bf ...........(2)

Subtracting (1) from (2), 2v=4bf−4af

⟹v=2f(b−a)

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