A 25 cm wide path is to be made around a circular garden having a diameter of 4 meters. Find the approximate area of the path in square meters.
Answers
Explanation:
Area of the path = Area of the outer circle – Area of the inner circle = ∏{4/2 + 25/100}2 – ∏[4/2]2
= ∏[2.252 – 22] = ∏(0.25)(4.25) { (a2 – b2 = (a – b)(a + b) }
= (3.14)(1/4)(17/4) = 53.38/16 = 3.34 sq m
Answer:
- Area of path made = 3.34 m²
Explanation:
- Width of the path to be made around the circular garden = 25 cm = (25/100) m = 0.25 m
- The Diameter of the Circular garden, d = 4 m
We need to find the approximate area of the Path in square metres.
So,
Since the diameter of Circular garden is = 4 m
therefore, the radius of Circular garden, r = 2 m
Hence,
→ Area of circular ground will be, A₁ = π r²
→ A₁ = π ( 2 )² = 4 π m²
Now,
When path of width 0.25 m will be made,
then new radius of Circular garden will be, R = 2 + 0.25 m = 2.25 m
Hence,
→ Area of circular garden along with path, A₂ = π R²
→ A₂ = π (2.25)² = 5.0625 π m²
So,
→ Area of path = A₂ - A₁
→ Area of path = (5.0625 π) - ( 4 π )
→ Area of path = 1.0625 π
→ Area of path = 1.0625 × 22/7
→ Area of path = 3.34 m² [Approx.]
Therefore,
- Area of path made around the circular garden would be 3.34 m² approximately.