A 25 gram metal ball is heated 200 degree c with 2330 calorie of energy what is the specific heat of the metal.Please ansswer guys
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Answer:
Q=mc(delta)T where
Q=2330
m=25g
delta T=200°C
c=?
Step-by-step explanation:
using formula, c=Q/mT
c=2330/25×200
= 2330/5000
= 0.466
Therefore C = 0.466 J/g°C.
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