Question

A 25 kg crate starting from rest at the top slides down a plane that makes an angle of 30 degree with the horizontal when it reaches the bottom of the 10 metre long slide its velocity is
8 metre per second the work done by the force of friction is closest to value of :​

Answer 1

Answer:

Mass of the block m=8 kg

Acceleration of the block a=0.4m/s

2

Since the block is sliding down the plane, so friction force acts backwards as shown.

Equation of motion along the inclined plane :

ma=mgsin30

o

−f

We get f=mgsin30

o

−ma

∴ f=(8)(10)(0.5)−(8)(0.4)

⟹f=36.8

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