A 25 litre solution contain 20% alcohol. If 50 litres of water are added to the solution, what percent of the new solution is alcohol ?
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% of alcohol in the solution = 20 %
Amount of solution = 25 L = 25000 ml
Amount of alcohol = 20/100 x 25000 = 5000 ml = 5 L
Amount of new solution = 25 L + 50 L = 75 L
Percentage of alcohol = x
= x/100 x 75 = 5
= x = 5 x 100/75
= x = 6.66.... %
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