Question

A 25 m long ladder is set against the wall of a house and just above reaches a window at height of 24 m above the ground level. how far is the lower end of the ladder from the base of the wall.

Answer 1

So the given things are AC = 25m
and AB =24m
In ΔABC,
using Pythagoras theorem
AC²=AB²+BC²
25²=24²+BC²
625=576+BC²
BC²=625-576=49
BC=√49
BC=7m
So the distance between the base to the lower part of ladder is 7m
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Answer 2

ladder wall and ground make together a right angle triangle
the length of leader is treat a hypotenuse wall is perpendicular and ground is base
so we know
$hypotenus { }^{2} = perpendicular {?}^{2} + base {?}^{2}$
hypotenuse=25
perpendicular=24
base=?
according to formula
$25 ^{2} = 24 {}^{2} + base {}^{2}$
$base {}^{2} = 25 \times 25 - 24 \times 24$
base^2=624-576
$base {}^{2} = 49$
after solving short
base=7
which is the distance between wall and lower end of leader