Question

A 25 metre ladder is leaning against the side of building and is positioned such that the base of the ladder is 7 from the base of the building how far above the ground is the point where the ladder touches the building

Pls answer the question with working

Answer 1

Answer:

ur answer in attachment

Step-by-step explanation:

hopes it helps you

Answer 2

Step-by-step explanation:

ANSWER:-

• The Hypotenuse is 25 metre
• The Base is 7 metre.
• We need to find the height.

Concept:-

How far above the ground is the point where the ladder touches the building ( Shows us to find the total height of the building)

$\setlength{\unitlength}{27} \begin{picture}(7,7) \linethickness{1} \put(1,1){\line(1,0){4}} \put(5,1){\line(0,1){6}}\qbezier(1,1)(1,1)(5,7)\put(0.8,0.7){ \bf B }\put(5,0.7){ \bf A }\put(5,7){ \bf C }\put(2.2,0.7){ \bf base = 7 \:m }\put(4.5,1){\line(0,1){0.5}}\put(4.5,1.5){\line(1,0){0.5}}\put( 0.5,4){ \bf Hypotenuse }\put(0.5,3.5){ \bf = 25 m }\put(5.2,4){ \bf Height }\put(5.2,3.5){ \bf = ? \: m }\put(0,5.5){\boxed{ \tt @MoonlightStarZ }}\end{picture}$

We know that:-

$\sf{Hypotenuse ^2= Base^2+Height^2}$

So, 2 components are already given.

We need to put the values.

$\sf{(25) ^2= (7)^2+Height^2}$

$\sf{625= 49+Height^2}$

$\sf{625= 49+Height^2}$

$\sf{625-49= Height^2}$

$\sf{ 576= Height^2}$

$\sf{ \sqrt{576}= Height}$

$\sf{24= Height}$

So, the height is 24 metres.

What we need to Remember:-

$\sf{Hypotenuse ^2= Base^2+Height^2}$

• Hypotenuse is the largest side of right angle Triangle.