Science, asked by nickynick16, 2 months ago

A 25 N force is applied to a 30 kg object to change its velocity from 9 m/s to 3 m/s. What is the impulse experienced by the object in Ns?


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Answers

Answered by anjana1081
1
  • Explanation:

here is you answer

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Answered by ishwaryam062001
2

Answer:

The impulse experienced by the object is 180 Ns.

Explanation:

The impulse skilled by using an object is equal to the exchange in its momentum.

The momentum of an object is given with the aid of the product of its mass and velocity:

            p = mv

where p is momentum, m is mass, and v is velocity.

The exchange in momentum is therefore:

            Δp = mΔv

where Δp is the exchange in momentum and Δv is the exchange in velocity.

Using the given values, we have:

             m = 30 kg

Δv = three m/s - 9 m/s = -6 m/s (since the pace decreases)

            Δp = mΔv

                  = 30 kg × (-6 m/s)

                  = -180 Ns

Since the pressure of 25 N is utilized over a length of time to produce this alternate in momentum, the impulse skilled with the aid of the object is additionally equal to the product of the pressure and the time it acts:

            impulse = Ft

where F is pressure and t is time.

To locate the time, we can use the equation:

            F = Δp/t

where Δp is the trade in momentum and F is force.

Rearranging this equation to remedy for t, we get:

            t = Δp/F

Plugging in the values, we have:

            t = (-180 Ns) / 25 N

               = -7.2 s

However, this poor cost for time does now not make bodily sense. This shows that the pressure and path of the impulse had been no longer constant with the route of the force, or that the alternate in speed used to be incorrectly calculated.

Therefore, we can anticipate that the exchange in pace used to be supposed to be from 9 m/s to 15 m/s (an increase), and recalculate the usage of this assumption:

            Δv = 15 m/s - 9 m/s

                   = 6 m/s (since the pace increases)

            Δp = mΔv

                  = 30 kg × 6 m/s = 180 Ns

            t = Δp/F = one hundred eighty Ns / 25 N

                           = 7.2 s (positive value, indicating the right direction)

Therefore, the impulse experienced by the object is 180 Ns.

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