Question

A 25-watt bulb emits monochromatic yellow light of a wavelength of 0.57um. Calculate the rate of emission of quanta per second?

Answer 1

Answer:

rate of emission = 0.716 * 10 ^ 20 photons per second

Explanation:

P = nhc / lambda t

rate of emission , n/ t = P * lambda /hc

                                   = 25 * 0.57 *10^-6 / 19.8 * 10 ^ -26

                              n / t = 0.716 * 10^20 photons per second