Question

A 250 kg bike is ridden by a circus man at
a speed of 20 m/sec. in a circular path of
diameter 100 m. Calculate its acceleration.​

Answer 1

its acceleration is 8 m/s²

it is given that, mass of bike ridden by man , m = 250 kg

speed of bike , v = 20m/s

diameter of circular path, d = 100m

so, radius of circular path , r = 50m

here, normal reaction acting by bike into circular path is balanced by centripetal force.

i.e., normal reaction = centripetal force

⇒ F = mv²/r

⇒ma = mv²/r

⇒ a = v²/r .......(1)

now putting, v and r values in equation (1)

we get, a = (20)²/50 = 400/50 = 8 m/s²

hence, acceleration is 8m/s²

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Answer 2

$\huge\bold\purple{Answer:-}$

It is given that,

Mass of the bike, m = 250 kg

Speed of the circus man on the circular path, v = 20 m/s

Diameter of the circle, d = 100 m

Radius of the circle, r = 50 m

Let a is the acceleration of the man on the circular path. The formula of the centripetal acceleration is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(20)^2}{50}

a=8\ m/s^2

So, the acceleration of the man is 8\ m/s^2. Hence, this is the required solution.