Question

A 250 mL buffer solution is prepared by using x g
of NH4CI and V mL of 1 M NaOH solution.
At pH = 9.6, the concentration of NH4+ ion in final
solution is 0.1 M. The value of x + V is (Kb of
NH4OH = 2 x 10-5)​

Answer 1

Answer:

Its a basic buffer pH=9;pOH=5

pOH=pK

b

+log[

(Base)

(Salt)

]

5=−log(108×10

−5

)+log[

NH

4

OH

NH

4

Cl

]

5=4.745+log[NH

4

Cl]

no. of Moles of NH

4

Cl added=1.8