Question

A 250 mL solution containing 21.4 g of polymer in toluene had an osmotic pressure of 0.055 atm at 27 oC. What is the formula mass of the polymer?

Answer 1

Answer:

I don't know this answer for your question

Answer 2

Given:

Volume of solution  is 250 $ml$ contain 21.4 $gm$ weight of polymer in toluene and osmotic pressure is 0.055 $atm$ at 27 °$c$.

To Find:

Formula mass of the polymer

Solution:

Equation of osmotic pressure-

Osmotic pressure (π) = C×R×T

C = Concentration or Molarity of solution in $molml^{-1}$

C= $\frac{W}{M}$×$\frac{1ooo}{V in ml}$

W = weight of polymer $gm$

M = Molecular mass of polymer $gmmol^{-1}$

R = gas constant $l atm mol^{-1} k^{-1}$

T = Temperature $k$

π = 0.055 $atm$

T= 27°$c$ ₊ 273 = 300 $k$

Weight of polymer = 21.4 $gm$

Volume = 250 $ml$

R = 0.0821  $l atm mol^{-1} k^{-1}$

Molecular mass of polymer = ?

Osmotic pressure = $\frac{W}{M}$×$\frac{1ooo *R *T}{V in ml}$

0.055 = $\frac{21.4}{M} \frac{1000*0.0821*300}{250}$

Molecular mass of polymer = approx 38000 $gm mol^{-1}$