a 250 watt electeic bulb is lighted for 5 hours daily and four 6 watt bulbs are lighted for 4.5 hours daily. calculate the energy consumed (in KwH) for the month of December
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Explanation:
250 watt bulb is lightened for 5 hours daily
& 6 watt bulb is lightened for 4.5 hours daily
A/q,
250×5 + 6× 4.5
= 1250+27
= 1277
= 1277/1000 KwH
= 1.277 KwH
hence, 1.277 KwH energy is consumed daily
therefore, Energy consumed in the month of December (= 31 days)
= (1.277× 31) KwH
= 39.587 KwH
Answer: 39.587 KwH
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