Question

A 250 watt electric bulb is lighted for 5 hours daily and four 6 watt bulbs are lighted for 4.5 hours daily.

Calculate the energy consumed (in kWh) in the month of February​

Answer 1

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First,taking 250 watt electric bulb which is lighted for 5 hours daily.

$\boxed{\textsf{W \: = \: P \: * \: t}}$

$\textsf{W \: = \: 250\: * \:5}$

$\textsf{W \:=\: 1250\: Whr/day.}$

Now, four 6 watt bulbs which are lighted for 4.5 hours daily.

$\textsf{W \:= \:4 \:* \:6 \:* \:4.5}$

$\textsf{W \:= \:108 \:Whr/day.}$

Total energy consumed per day = 1250 + 108 = 1358 Whr/day.

Converting to kWh,

$\textsf{1 \:Whr \:= \:0.001 \:kWh}$

$\textsf{1358\: * \:0.001}$

$\boxed{\textsf{1.358 \: kWh/day}}$

Number of days in February = 28 days.

Total power consumed in the month of February = 1.358 * 28

$\boxed{\textsf{38.024 \: kWh}}$

$\huge{\bf{\pink{\mathfrak{Conclusion:-}}}}$

$\boxed{\therefore{\textsf{Energy \: consumed \: in \: the \: month \: of \: February \: = \: 38.024 \: kWh.}}}$

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