a 250-watt electric bulb is lighted for 5 hours daily and four 6-watt bulbs are lighted for 4.5 hours daily. calculate the energy consumed (in kwh) in the month of february.
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2
Answer:
Step-by-step explanation:
Hello!
• Electricity consumed by bulb and light bulb
• Energy=250 x 5+6 x 4 x 4.5
=0.108+1.25
• 1.358 kilo watt hour in a day
• Now electricity consumed in 28 days
1.358 x 28
• =38.024 units
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Answered by
4
Step-by-step explanation:
Total power consumed by 6 watt bulbs
= 4×4.5 ×28× 6 Joule
= 3024 Joule
Total power consumed by 250 bulb
=250× 28× 5 Joule
= 35000 Joule
Total power consumed =(35000+ 3024)J=38,024J
Total energy consumed=38.024 B.O.T
Hope it will help you....
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