Question

A 250 watt electric bulb is lighted for 5 hours daily and four 6 watt bulbs are lighted for 4.5 hours daily. Calculate the energy consumed (in kWh) in the month of February.

Answer 1

Answer:

250*5 watts *28 days= 35 units in Feb month

and 4.5 WATS * 6*28= .756 unit

Explanation:

answer is .756 watt

Answer 2

$\huge{\bf{\green{\mathfrak{Question:-}}}}$

• A 250 watt electric bulb is lighted for 5 hours daily and four 6 watt bulbs are lighted for 4.5 hours daily. Calculate the energy consumed (in kWh) in the month of February.

$\huge {\bf{\orange{\mathfrak{Answer:-}}}}$

• First, taking 250 watt electric bulb which is lighted for 5 hours daily.

• $\boxed{\textsf{W \: = \: P \: * \: t}}$

• $\textsf{W \: = \: 250\: * \:5}$

• $\textsf{W \:=\: 1250\: Whr/day.}$

• Now, four 6 watt bulbs which are lighted for 4.5 hours daily.

• $\textsf{W \:= \:4 \:* \:6 \:* \:4.5}$

• $\textsf{W \:= \:108 \:Whr/day.}$

• Total energy consumed per day = 1250 + 108 = 1358 Whr/day.

• Converting to kWh,

• $\textsf{1 \:Whr \:= \:0.001 \:kWh}$

• $\textsf{1358\: * \:0.001}$

• $\boxed{\textsf{1.358 \: kWh/day}}$

• Number of days in February = 28 days.

• Total power consumed in the month of February = 1.358 * 28

• $\boxed{\textsf{38.024 \: kWh}}$

$\huge{\bf{\red{\mathfrak{Conclusion:-}}}}$

• $\boxed{\therefore{\textsf{Energy \: consumed \: in \: the \: month \: of \: February \: = \: 38.024 \: kWh.}}}$