Physics, asked by Anonymous, 3 months ago

A 250 watt electric bulb is lighted for 5 hours daily and four 6 watt bulbs are lighted for 4.5 hours daily. Calculate the energy consumed (in kWh) in the month of February.
.
.
.
PLZ anyone ans this question...​

Answers

Answered by Anonymous
8

Answer:

Ab correct hai

hope helps u

Attachments:
Answered by Anonymous
2

{\fcolorbox{blue}{black}{{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:Answer\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:}}}

250 watts multiplied with 5 hours daily multiplied with 30 days monthly equals 37500 Watt hours. Divided by a 1000 to get the KWh equals 37.5 KWh.

Four 6 watt lightbulbs equals 24 watts because 4x6=24

So 24 watts multiplied with 4.5 hours daily multiplied with 30 days monthly equals 3240 watt hours . Divided by a 1000 to get the KWh equals 3.24 KWh.

So 37.5 KWh plus 3.24 KWh equals 40.74 KWh a month if the month has 30 days.

40.74 KWh multiplied by the price of 1 KWh will give you the monthly price you pay for using that high energy consuming lightbulb.

I'm not spending that much for powering the whole apartment not yet a for a single bulb. .you must be a dentist or a brain surgeon.

still try this

250*5 watts *28 days= 35 units in Feb month

and 4.5 WATS * 6*28= .756 unit

Similar questions