A 250 watt electric bulb is lighted for 5 hours daily and four 6watt bulbs lighted for 4.5 hours daily. Calculate the energy consumed (in KWh) in the month of February .
Answers
energy=250into 5+6into4into 4.5
=0.108+1.25
1.358kwh in a day
now electricity consumed in 28 days
1.358into28
=38.024 units
Given,
Power of the first type of electric bulb = 250 Watt
Per day usage of this bulb = 5 hours
Power of the second type of electric bulb = 6 Watt
Per day usage of this bulb = 4.5 hours
To find,
Total energy consumed (in KWh) in February.
Solution,
We can simply solve this numerical problem by using the following process:
Mathematically,
Power (P)
= Energy consumed (E) ÷ Time (T)
=> Energy consumed (E) = Power (P) x Time (T)
Now,
Total units of energy consumed in one day by the first type of electric bulb = Power (P) x Time (T)
= 250 W x 5 hours
= 1250 Wh = 1.25 kWh = 1.25 electrical units
( Since 1 kWh = 1 electrical unit )
So, the total units of energy consumed in February by the first type of electric bulb = 1.25 electrical units × 28 days
= 35 electrical units
= 35 kWh
Now,
Total units of energy consumed in one day by each of the second type of electric bulb = Power (P) x Time (T)
= 6 W x 4.5 hours
= 27 Wh = 0.027 kWh = 0.027 electrical units
( Since 1 kWh = 1 electrical unit )
So, the total units of energy consumed in February by all four of the second type of electric bulb = 0.027 electrical units × 4 × 28 days
= 3.024 electrical units
= 3.024 kWh
Now,
Total energy consumed (in KWh) in February
= (the total units of energy consumed in February by the first type of electric bulb) + (the total units of energy consumed in February by all four of the second type of electric bulb)
= 35 electrical units + 3.024 electrical units
= 38.024 electrical units
= 38.024 kWh
Hence, the total energy consumed (in KWh) in February is equal to 38.024 kWh, that is 38.024 electrical units.