A 250 watt is used to heat 500g of mercury. The heater is on for one minute and the initial temperature of mercury is 20 degree celsius calculate the final temperature of mercury if specific heat of mercury is 0.14 joule per gram degree Celsius .
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anushree81:
what's the solution
use this formula
The formula I know but I want solution
ok
is answer 448
how
I don't know
what's the answer
I don't know that's why I asked the question
hey
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Hola User____________________
Here is your Answer...!!!
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↪Actually welcome to the concept of the CALORIMETRY.
↪BAsically here we will use the formula of the ...
↪〽⭐Q = m s ♢t
↪since here m = mass , Q = heat , s = specific heat and ♢T = change in temperature
↪so here first we convert the power into joules as we know that . ..
↪Power = joules / sec ... since here the heater is on for 60 seconds ..
↪thus the heat energy will be = 250 × 60= 15000 joules ...
↪so after solving we get as ...
_____________________________
Here is your Answer...!!!
____________________________
⭐
↪Actually welcome to the concept of the CALORIMETRY.
↪BAsically here we will use the formula of the ...
↪〽⭐Q = m s ♢t
↪since here m = mass , Q = heat , s = specific heat and ♢T = change in temperature
↪so here first we convert the power into joules as we know that . ..
↪Power = joules / sec ... since here the heater is on for 60 seconds ..
↪thus the heat energy will be = 250 × 60= 15000 joules ...
↪so after solving we get as ...
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