a 250 watt of heater is used to heat 500 g of mercury.The heater is on for 1 minute and initial temperature of mercury is 20'c.Calculate the final temperature of mercury provided the heat capacity of mercury is 0.15jg-1'c-1
Answers
Explanation:
Theoretical Assumptions (not realistic): 1) ALL of the heat energy is transferred to the water, and 2)the water is uniformly heated. 3) The water density is 1.0g/mL.
Because we are only heating it TO the “boiling point”, ONLY the energy to heat the water from 20 to 100’C using the heat capacity or specific heat of water is required. A “Watt” is 1 Joule/second. The specific heat of water is 4.184 J/g-’C. Water mass is 1000g. The energy required to heat it is therefore
1000g⋅4.184(
J
g
’C)⋅(100−20)’C=334720J
The heater supplies 1200 J/s, so the time to provide this heat to the water is 334720
J
1200(
J
s
)
=278.9s or 4.65 minutes.
SORRY BUT HERE VALUES ARE CHANGE
Answer:
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