Question

A 25cm wide path is to be made around a cirular garden having a diameter of 4m app.area of the path in square meters is

Answer 1

Answer:

Area of the path = Area of the outer circle – Area of the inner circle = ∏{4/2 + 25/100}2 – ∏[4/2]2

= ∏[2.252 – 22] = ∏(0.25)(4.25) { (a2 – b2 = (a – b)(a + b) }

= (3.14)(1/4)(17/4) = 53.38/16 = 3.34 sq m

Step-by-step explanation:

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Answer 2

Answer:

Area of path made = 3.34 m²

Step-by-step explanation:

Width of the path to be made

around the circular garden = 25 cm = (25/100) * m = 0.25m The Diameter of the Circular garden, d = 4m

We need to find the approximate area of the Path in square metres.

So,

Since the diameter of Circular garden is = 4 m

therefore, the radius of Circular garden, r

= 2 m

Hence,

→ Area of circular ground will be, A_{1} = Pi * r ^ 2

→ A₁ = πT (2)² = 4π m²

Now,

When path of width 0.25 m will be made,

then new radius of Circular garden will

be, R = 2 + 0.25 m = 2.25 mNow,

When path of width 0.25 m will be made, then new radius of Circular garden will

be, R = 2 + 0.25 m = 2.25 m

Hence,

→ Area of circular garden along with path, A_{2} = Pi * R ^ 2

→ A₂ = πT (2.25)² = 5.0625 π m²

So,

→ Area of path = A₂ - A₁

→ Area of path = (5.0625 ) - ( 4 )

→ Area of path = 1.0625 T

→ Area of path = 1.0625 × 22/7

→ Area of path = 3.34 m² [Approx.]

Therefore,

Area of path made around the circular garden would be 3.34 m² approximately.