A 25g bullet leaves a rifle with a velocity of 100 ms-1
. If the rifle recoils with a velocity of
100 cm/s, what is the mass of the rifle?
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Answer:
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Explanation:
according to law of conservation of momentum
MU + mu = MV + mv
Let M = 2.5 kg
m = m kg
initial velocity = 0 ( cause both were at rest before firing)
V = -1 m/s (it acts in opp. direction)
v = 100 m/s
2.5 X 0 + m x 0 = 2.5 x -1 + m X 100
0 = -2.5 + 100m
2.5 = 100m
25/1000 or 0.025 = m <= answer
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