A 25g of unpurified calcium carbonate was heated, after heating 14.8g remained ,the percentage of contamination in the solution is?
Answers
Answered by
1
40.8%
Explanation:
25-14.8
10.2
10.2/25×100
40.8percent
Answered by
2
Answer:
gbghvchvgjbbhhhggfcfhh
Similar questions