A 25kg box is pulled at a constant speed by a horizontal force on a horizontal floor .The coefficient of sliding friction between the box and the floor is 0.20.How much work is done in pulling the box through 20m?
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8
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➧ Work = force × displacement cosθ
➧ Force of friction =
Coefficient of friction × normal reaction
➾ 0.2 × mg
➾ 0.2 × 25 × 10
➾ 50 N
➧ Force × displacement
➾ 50N × 20 m
➾ 1000 J ...✔
_________
Thanks...✊
▬▬▬▬▬▬▬▬▬▬▬▬☟
➧ Work = force × displacement cosθ
➧ Force of friction =
Coefficient of friction × normal reaction
➾ 0.2 × mg
➾ 0.2 × 25 × 10
➾ 50 N
➧ Force × displacement
➾ 50N × 20 m
➾ 1000 J ...✔
_________
Thanks...✊
Answered by
7
Answer:
Mass of box m = 25 kg,
µ = 0.20,
S = 20 m,
g = 9.8 ms^−2
.
Frictional force acting on the block
f = µN
= µmg
= 0.20 x 25 x 9.8
= 49 N.
Minimum force needed to move the block F = 49 N.
Work done by the force F = FS
= 49×20
= 980 J.
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