Question

A 25kg box is pulled at a constant speed by a horizontal force on a horizontal floor .The coefficient of sliding friction between the box and the floor is 0.20.How much work is done in pulling the box through 20m?

Answer 1

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➧ Work = force × displacement cosθ

➧ Force of friction =
Coefficient of friction × normal reaction
➾ 0.2 × mg

➾ 0.2 × 25 × 10
➾ 50 N

➧ Force × displacement

➾ 50N × 20 m
➾ 1000 J ...✔

_________
Thanks...✊

Answer 2

Answer:

Mass of box m = 25 kg,

µ = 0.20,

S = 20 m,

g = 9.8 ms^−2

.

Frictional force acting on the block

f = µN

= µmg

= 0.20 x 25 x 9.8

= 49 N.

Minimum force needed to move the block F = 49 N.

Work done by the force F = FS

= 49×20

= 980 J.