Question

A 25m ladder is placed on a wall such that its foot is placed 7m away from the wall. Find the length of the wall

Answer 1

✬ Wall = 24 m ✬

Step-by-step explanation:

Given:

• Length of ladder is 25 m.
• Distance between foot of wall and ladder is 7 m.

To Find:

• What is the length of wall ?

Solution: Let AB be a wall , AC is ladder or 25 m , BC is Distance between foot of wall and ladder.

In ∆ABC right angled at B , we have

• AB = ? (Perpendicular)
• BC = 7 m (Base)
• AC = 25 m (Hypotenuse)

Applying Pythagoras Theorem

★ H² = B² + P² ★

$\implies{\rm }$ AC² = BC² + AB²

$\implies{\rm }$ 25² = 7² + AB²

$\implies{\rm }$ 625 = 49 + AB²

$\implies{\rm }$ 625 – 49 = AB²

$\implies{\rm }$ 576 = AB²

$\implies{\rm }$ √576 = AB

$\implies{\rm }$ 24 = AB

Hence, length of wall is 24 m.

Answer 2

Answer:

,

Step-by-step explanation:

✬ Wall = 24 m ✬

Step-by-step explanation:

Given:

Length of ladder is 25 m.

Distance between foot of wall and ladder is 7 m.

To Find:

What is the length of wall ?

Solution: Let AB be a wall , AC is ladder or 25 m , BC is Distance between foot of wall and ladder.

In ∆ABC right angled at B , we have

AB = ? (Perpendicular)

BC = 7 m (Base)

AC = 25 m (Hypotenuse)

Applying Pythagoras Theorem

★ H² = B² + P² ★

\implies{\rm }⟹ AC² = BC² + AB²

\implies{\rm }⟹ 25² = 7² + AB²

\implies{\rm }⟹ 625 = 49 + AB²

\implies{\rm }⟹ 625 – 49 = AB²

\implies{\rm }⟹ 576 = AB²

\implies{\rm }⟹ √576 = AB

rm⟹ 24 = AB

Hence, length of wall is 24 m.