A 25meter ladder is placed against a vertical wall that the foot of the ladder is 7 meter from the foot if the wall. if the top of the ladder slides down by 4meter by how much distance will the foot of the ladder slide?
Answers
Answered by
2
let height of the wall, where ladder is placed, is x
then by Pythagoras theorem
25²=x²+7²
or x²=25²-7²
or x²=(25+7)(25-7)
or x²=32*18
or x=8*3
or x=24
if it falls 4 metre then height will be 20
then distance between foot of the ladder and wall will be y² =25²-20²
or y²=(25+20)(25-20)
or y²=45*5
or y²=3*5
or y=15................(ans)
then by Pythagoras theorem
25²=x²+7²
or x²=25²-7²
or x²=(25+7)(25-7)
or x²=32*18
or x=8*3
or x=24
if it falls 4 metre then height will be 20
then distance between foot of the ladder and wall will be y² =25²-20²
or y²=(25+20)(25-20)
or y²=45*5
or y²=3*5
or y=15................(ans)
Similar questions