A 25N force F is applied to a bar that can pivot around its end as shown below.
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Answered by
4
Answer:
9.375Nm
Explanation:
The formula for calculating torque τ = Frsin∅ where;
F = applied force (in newton)
r = radius (in metres)
∅ = angle that the force made with the bar.
Given F= 25N, r = 0.75m and ∅ = 30°
torque on the bar τ = 25*0.75*sin30°
τ = 25*0.75*0.5
τ = 9.375Nm
The torque on the bar is 9.375Nm
Answered by
1
Explanation:
Answer:9.375NmExplanation:The formula for calculating torque τ = Frsin∅ where;F = applied force (in newton)r = radius (in metres)∅ = angle
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