Question

A 26 m long ladder is pleased against the wall in such a way that the foot of the ladder is 10 m away from the wall .how up in the wall is the upper land of the ladder?

Answer 1

Answer:

jst by pythagoras theorem..

$H^2=P^2+B^2$

$26^2=P^2+10^2$

$676=P^2+100$

$P^2=676-100$

$P^2=576$

$P=24$

Answer 2

hence answer is 24.

.........