A 26 m long ladder leans against a wall. If the top of the ladder touches the wall 24 m
above the ground, find the distance between the foot of the ladder and foot of the wall
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Answer:
10 m
Step-by-step explanation:
As you can see this is a form of triangle where
26 m = is the hypotenuse
24 m = is the distance above the ground surface. i.e. b/w top of the wall and foot of the ground.
b/w foot of the ladder and foot of the ground = ?
so here by using pythagoras theorem you can say
AB^2 = BC^2 + AC^2
26^2 = 24^2 + AC^2
AC^2 = 676 - 576
AC^2 = 100
so,
AC = 10 m
thank you
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