A 26m ladder is placed at A. If it is placed along wall PQ it reaches a height of 24m whereas it reaches a height of 10m if it is placed against wall RS. Find the distance between these walls.
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Answer:
34 mts
Step-by-step explanation:
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Answer:
34 Metre...
Step-by-step explanation:
In the triangle BQA, <Q = 90
By Pythagoras theorem..
(H)^2=(P)^2-(B)^2
26*26 = 24*24 -(B)^2
√676-576=B
B = 10 Metre..
In the triangle ABC, B = 90
By Pythagoras theorem...
26*26 = 10*10 -(B)^2
√676-100 = B
B = 24 metre.
total distance between walls = 24 + 10 = 34.
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