Question

A 26m LADDER REACHED A WINDOW 24 m HEIGHT FROM THE GROUND ON PLACING IT AGAINST A WALL AT A DISTANCE d .FIND THE DISTANCE OF THE FOOT OF THE LADDER FROM jni THE WALL​

Answer 1

In △PQR, we have

PR2=PQ2+QR2

(By Pythagoras theorem)

(26)2=(24)2+QR2

QR2=676−576=100

⇒QR=100

⇒QR=10

The distance of the foot of the ladder fro the wall is 10 m.

Hope it helps :)