Question

A) -273 degree Celsius
B) 284.7k
C) 300 c
D) -136.5 c

Answer asap please

Answer 1

Answer:

_273 degree Celsius

it's Answer

Answer 2

GIVEN :

• Initial temperature ( T₁ ) of gas = 0° C
• Pressure is constant

To find :

Temperature at which volume of gas reduce to half

Solution :

Let -

• Initial Volume = V₁
• Final Temperature = T₂
• Final volume = V₂

Now , We can apply Charles Law as Pressure is constant.

Charles Law , states that at constant pressure volume of gas is directly proportional to its temperature in Kelvin scale.

That is , V ∝ T

$\sf \implies \: \dfrac{V_1}{V_2} \:=\: \dfrac{T_1}{T_2} \: \: \: ......equation \: 1$

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Now we need to find Temperature in Kelvin scale

➝ T₁ = 0 + 273

➝ T₁ = 273 K

Also , volume reduce to half

➝ V₂ = V₁ ÷ 2

$\sf \implies \: \dfrac{ \: \: \: V_1 \: \: \: }{ \dfrac{V_1}{2} } \:=\: \dfrac{273}{T_2}\\ \\ \\ \sf \implies \: \: \: \: V_1 \: \times \: \dfrac{2}{V_1} \:=\: \dfrac{273}{T_2} \\ \\ \sf \implies \: \:\dfrac{273}{T_2} \: = \: 2 \\ \\ \sf \implies \: \:\dfrac{273}{2} \: = \: T_2 \\ \\ \sf \implies \: \: \: T_2 \: = \: 136.5 \: K$

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Now , T₂ = 136.5 K

Converting it into Celcius,

T₂ = 136.5 - 273

T₂ = -136.5° C

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ANSWER :

Option D) -136.5° C