Question

A 280 liters mixture contains liquid A and B in a certain ratio. If 40 liters liquid B is
added to the mixture, the ratio of liquid A and B becomes reverse. What is the
initial quantity of liquid B2
280 लीटर मिश्रण में एक निक्षित अनुपात में तरल A और तस्ल Bहोता है। यदि 40 लीटर तरत:
को मिश्रण में मिलाया जाता है. तो तरतA और B का अनुपात व्युत्क्रम हो जाता है। तरल की
प्रारभिक मात्रा कितनी है?
a)130(2/3) liters
b) 125 liters
c)128(1/3)liters
d) 132 liters
e)115Eters​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

Given in the question is that A 280 liters mixture contains liquid A and B in a certain ratio. we have to find What is the initial quantity of liquid B2 if 40 liters liquid B is added to the mixture, the ratio of liquid A and B becomes reverse.

forming the questions on the basis of data given:

let us suppose the volume of A= x

the, volume of B = 280-x

ratio= $x/280-x$

now let us add 40 liters of B to the mixture then ,

$A= x\\B= (280-x)+40$$= 320-x$

According to question,

$x/(320-x) = (280-x)/x\\x^2= (320*280) - 600x +x^2\\x= 320*280/600\\x= 149.33 liters$

thus quantity of B = 130.66 Liters

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