A 29.1-kg sledder is travelling along a level area with a speed of 8.96 m/s when she approaches a gentle incline which makes an angle of 12.5 degrees with the horizontal. If the coefficient of friction between the sled and the incline is 0.109, then what will be her speed at the bottom of the inclined plane, located 8.21 m above the top of the incline. Do not forget to mention the units
Answers
Answer:
I hope this will help you
Explanation:
This is an example of energy transformation from potential energy at the highest point (the point of release) to kinetic energy at the lowest position. Since gravity is the only force doing work (tension acts perpendicular to the displacement so it does not do work), the total mechanical energy is conserved. So the energy conservation equation will be used.
KEi + PEi = KEf + PEf
Since the child starts from rest, the KEi term can be canceled. And if we assign the lowest position as the zero-level, then the PEf term can be canceled from the equation. The equation can be rewritten as
PEi = KEf
By substituting in expressions for kinetic and potential energy, the equation becomes
m • g • hi = 0.5 • m • vf2
The mass cancels from each side of the equation, and algebra can be used to manipulate the equation to solve for