a (2a+3b^2-4(3a-4b)^2
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0
Answer:
I donot know
Step-by-step explanation:
you do in google please bro
Answered by
1
Step-by-step explanation:
Answer:
\begin{gathered}(2 {a}^{2} + 3 {b}^{2} + 6ab) - 4(3 {a}^{2} + 4 {b}^{2} - 12ab) \\ 2 {a}^{2} + 3 {b}^{2} + 6ab - 12 {a}^{2} - 16 {b}^{2} + 48ab \\ - 10 {a}^{2} - 13 {b}^{2} + 36\end{gathered}
(2a
2
+3b
2
+6ab)−4(3a
2
+4b
2
−12ab)
2a
2
+3b
2
+6ab−12a
2
−16b
2
+48ab
−10a
2
−13b
2
+36
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