Question

a (2a+3b^2-4(3a-4b)^2​

Answer 1

Answer:

$(2 {a}^{2} + 3 {b}^{2} + 6ab) - 4(3 {a}^{2} + 4 {b}^{2} - 12ab) \\ 2 {a}^{2} + 3 {b}^{2} + 6ab - 12 {a}^{2} - 16 {b}^{2} + 48ab \\ - 10 {a}^{2} - 13 {b}^{2} + 36$

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Answer 2

Answer:

\begin{gathered}(2 {a}^{2} + 3 {b}^{2} + 6ab) - 4(3 {a}^{2} + 4 {b}^{2} - 12ab) \\ 2 {a}^{2} + 3 {b}^{2} + 6ab - 12 {a}^{2} - 16 {b}^{2} + 48ab \\ - 10 {a}^{2} - 13 {b}^{2} + 36\end{gathered}

(2a

2

+3b

2

+6ab)−4(3a

2

+4b

2

−12ab)

2a

2

+3b

2

+6ab−12a

2

−16b

2

+48ab

−10a

2

−13b

2

+36